Bonjour jai besoin daide svp Calculer ces expressions et donner le résultat sous la forme d'une fraction irreductible merci de maider svp

Bonsoir,

a = 3/2 ; b = - 3 ; c = 1/6

M = a + b x c

M = 3/2 - 3 x 1/6

M = 3/2 - 3/6

M = 3/2 - (3 x 1) / (3 x 2)

M = 3/2 - 1/2

M = 2/2

M = 1

N = (a - c) : b

N = (3/2 - 1/6) : - 3

N = [(3 x 3) / (2 x 3) - 1/6] : - 3

N = (9/6 - 1/6) : - 3

N = 8/6 x - 1/3

N = - 8/18

N = (2 x - 4) / (2 x 9)

N = - 4/9.

P = a x b/c

P = 3/2 x - 3 : 1/6

P = - 9/2 x 6

P = - 54/2

P = - 27.

M = a + b x c

M = 3/2 + (-3) x 1/6

M = 3/2 - 3/6          ici  3/6 = 3x1/3x2 = 1/2

M = 3/2 - 1/2

M = 2/2

M = 1

N= ( a - c) : b

N = (3/2 - 1/6) : -3      dans la () on met au meme dénominateur 6

N = (3x3/2x3 - 1/6)

N = (9/6 - 1/6) : -3

N = 8/6 : - 3              8/6 on peu simplifier par 2 = 2x4 / 2x3 = 4/3

N = 4/3 : -3          diviser une fraction revient à la X par son inverse

N = 4/3 x -1/3

N = - 4x1 / 3x3

N = - 4 / 9

P = a x b/c

P = 3/2 x -3 : 1/6

P = 3 x -3/2 : 1/6

P = -9/2 : 1/6

P = -9/2 x 6

P= - 9x6 /6

P = - 54/2

P = - 27