Mathématiques

Question

aider moi svp
factorisations
aider moi svp factorisations

2 Réponse

  • A=(x+2)(-2x-3)+x+2=(x+2)(-2x-3+1)=(x+2)(-2x-2)=-2(x+2)(x+1)

    B=-(x+2)^2+3(x+2)(-x+1)+5(x+2)=(x+2)(-(x+2)+3(-x+1)+5)=(x+2)(-x-2-3x+3+5)=(x+2)(-4x+6)=2(x+2)(-2x+3)

    C=(t+1)(-2t+3)-2(t+1)^2+(t+1)(3t+4)=(t+1)(-2t+3-2(t+1)+3t+4)=(t+1)(-2t+3-2t-2+3t+4)=(t+1)(-t+5)

    D=(x+3)(2x+1)+(2x+6)(-5x+1)=(x+3)(2x+1)+2(x+3)(-5x+1)=(x+3)(2x+1+2(-5x+1))=(x+3)(2x+1-10x+2)=(x+3)(-8x+3)

    E=(x-1)^2+2(-x+1)(x+3)=(x-1)^2-2(x-1)(x+3)=(x-1)(x-1-2(x+3))=(x-1)(x-1-2x-6)=(x-1)(-x-7)=-(x-1)(x+7)
  • Salut,

    [tex]A(x) = (x+2)(-2x-3) + x+2 \\ A(x) = (x+2)(-2x-3) + (x+2)*1 \\ A(x) = (x+2)[-2x - 2 + 1]\\ A(x) = (x+2)(-2x -1) \\ B(x) = -(x+2)^{2} + 3(x+2)(-x+1) + 5(x+2) \\ B(x) = (x+2) [3(-x+1) - (x+2) + 5]\\ B(x) = (x+2)(-2x + 3 -x - 2 + 5)\\ B(x) = (x+2)(-3x + 6)\\ B(x) = 3(x+2)(2-x)\\ C(t) = (t+1)(-2t+3)-2(t+1)^{2} + (t+1)(3t+4) \\ C(t) = (t+1)[-2t+3 -2(t+1) + (3t+4)]\\ C(t) = (t+1)(-2t + 3 -2t - 2 + 3t + 4)\\ C(t) = (t+1)(-t +2)[/tex]
    [tex]D(x)= (x+3)(2x+1) + (2x+6)(-5x+1) \\ D(x) = (x+3)(2x+1)+ 2(x+3)(-5x+1) \\ D(x) = (x+3)[(2x + 1) + 2(-5x+1)]\\ D(x) = (x+3)(2x+1-10x + 2)\\ D(x) = (x+3)(-8x + 3)\\[/tex]
    [tex]E(x) = (x-1)^{2} + 2(-x+1)(x+3) \\ E(x) = (x-1)^{2} - 2(x-1)(x+3)\\ E(x) = (x-1)[x-1 - 2(x+3)]\\ E(x) = (x-1)(x-1 - 2x - 6 )\\ E(x) = (x-1) (-x -7)\\ E(x) = -(x-1)(x+7)[/tex]

    Bonne soirée !