bonjour factoriser: 3-x+(3-x)^2 (x-2)(x+3)+x^2-4x+4 merci
Mathématiques
mistigrou
Question
bonjour
factoriser:
3-x+(3-x)^2
(x-2)(x+3)+x^2-4x+4
merci
factoriser:
3-x+(3-x)^2
(x-2)(x+3)+x^2-4x+4
merci
1 Réponse
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1. Réponse Anonyme
Bonsoir,
3-x+(3-x)² = (3-x)(1)+(3-x)(3-x)
= (3-x)[1+(3-x)]
= (3-x)(4-x)
(x-2)(x+3)+x²-4x+4 = (x-2)(x+3)+(x-2)²
= (x-2)(x+3)+(x-2)(x-2)
= (x-2)[(x+3)+(x-2)]
= (x-2)(2x+1)